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I activities) Help 2 of 5 Constants Periodic Table ing chemical reactions in the lab or in sses, it can be important to know ion has reached equilibrium. By eaction quotient, Q, of a chemical mparing it to the equilibrium can identify whether a reaction is +bBcC+dD ent, Q, is given by the expression $a(C)^c a(D)^d \over a(A)^a a(B)^b$ ns, where a(C) is the unitless qual to K only at equilibrium. The following reaction was carried out in a 2.00 L reaction vessel at 1100 K: C(s)+H$_2$O(g)CO(g) + H$_2$(g) If during the course of the reaction, the vessel is found to contain 8.25 mol of C, 13.9 bar of H$_2$O, 3.60 bar of CO, and 8.80 bar of H$_2$. what is the reaction quotient Q? Enter the reaction quotient numerically. ? View Available Hint(s) Q=0 ? ??? Submit Previous Answers ?X Incorrect; Try Again; 5 attempts remaining Part C The reaction 2CH$_4$(g)CH$_2$(g)+3H$_2$(g)

          I activities)
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2 of 5
Constants Periodic Table
ing chemical reactions in the lab or in
sses, it can be important to know
ion has reached equilibrium. By
eaction quotient, Q, of a chemical
mparing it to the equilibrium
can identify whether a reaction is
+bBcC+dD
ent, Q, is given by the expression
$a(C)^c a(D)^d \over a(A)^a a(B)^b$
ns, where a(C) is the unitless
qual to K only at equilibrium.
The following reaction was carried out in a 2.00 L reaction vessel at 1100 K:
C(s)+H$_2$O(g)CO(g) + H$_2$(g)
If during the course of the reaction, the vessel is found to contain 8.25 mol of C, 13.9 bar of H$_2$O, 3.60 bar of CO, and 8.80
bar of H$_2$. what is the reaction quotient Q?
Enter the reaction quotient numerically.
? View Available Hint(s)
Q=0
? ???
Submit Previous Answers
?X Incorrect; Try Again; 5 attempts remaining
Part C
The reaction
2CH$_4$(g)CH$_2$(g)+3H$_2$(g)
        
Show more…
I activities)
Help
2 of 5
Constants Periodic Table
ing chemical reactions in the lab or in
sses, it can be important to know
ion has reached equilibrium. By
eaction quotient, Q, of a chemical
mparing it to the equilibrium
can identify whether a reaction is
+bBcC+dD
ent, Q, is given by the expression
a(C)^c a(D)^d  a(A)^a a(B)^b
ns, where a(C) is the unitless
qual to K only at equilibrium.
The following reaction was carried out in a 2.00 L reaction vessel at 1100 K:
C(s)+H2O(g)CO(g) + H2(g)
If during the course of the reaction, the vessel is found to contain 8.25 mol of C, 13.9 bar of H2O, 3.60 bar of CO, and 8.80
bar of H2. what is the reaction quotient Q?
Enter the reaction quotient numerically.
? View Available Hint(s)
Q=0
? ???
Submit Previous Answers
?X Incorrect; Try Again; 5 attempts remaining
Part C
The reaction
2CH4(g)CH2(g)+3H2(g)

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Nivaldo Tro 2nd Edition
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Help 2 of 5 The following reaction was carried out in a 2.00L reaction vessel at 1100K: Constants Periodic Table When studying chemical reactions in the lab or in classes, it can be important to know when a reaction has reached equilibrium. By calculating the reaction quotient, Q, of a chemical reaction and comparing it to the equilibrium constant K, we can identify whether a reaction is at equilibrium or not. aA + bB ⇌ cC + dD The reaction quotient, Q, is given by the expression Q = (a(C)^c * a(D)^d) / (a(A)^a * a(B)^b) where a(C) is the unitless activity of C. It is important to note that Q is equal to K only at equilibrium. C(s) + H2O(g) ⇌ CO(g) + H2(g) If during the course of the reaction, the vessel is found to contain 8.25 mol of C, 13.9 bar of H2O, 3.60 bar of CO, and 8.80 bar of H2, what is the reaction quotient Q? Enter the reaction quotient numerically. View Available Hint(s) Q = Previous Answers Incorrect; Try Again; 5 attempts remaining Part C The reaction 2CH4(σ) ⇌ CoHO(σ) + 3H2(σ) is equal to K only at equilibrium. It is important to note that a(C) is the unitless activity. The reaction quotient, Q, is given by the expression aCaD ent, Q, is given by the expression r + bBcC + dD can identify whether a reaction is studying chemical reactions in the lab or in The reaction Part C Submit 0 Q = A View Available Hints X Incorrect; Try Again; 5 attempts remaining Previous Answers Enter the reaction quotient numerically. The following reaction was carried out in a 2.00L reaction vessel at 100K Cs + HOg = COg + Hg Constants Periodic Table 215 Help
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G.C. 2-7: LABORATORY REPORT Name: Answer the following questions in your laboratory notebook in complete detail using Le chatelier's principle to explain and support your observations. Include the direction of the reaction shift in all answers. System No. 1: HC2H3O2(aq) ⇌ H+(aq) + C2H3O2-(aq) Solutions | pH | Observation 0.1 M HC2H3O2 | 3 | Dark orange/ reddish color 0.1 M HC2H3O2 + NaC2H3O2 | 5 | light orange 1. Did the equilibrium shift and in which direction? 2. How did the pH of the solution change after adding NaC2H3O2 to it? (Hint: Identify which ion is being added to the solution and how it affects the concentration of other ions present in solution.) System No. 2: 2CrO4^2-(aq) + 2H+(aq) ⇌ Cr2O7^2-(aq) + H2O(l) Solutions | Observations Na2CrO4 solution | yellow Na2CrO4 solution + HCl | orange Na2CrO4 solution + NaOH | yellow 3. Explain how the equilibrium shifted when you added HCl to the solution? 4. Which chromium ion is orange and which is yellow? How did you know? 5. How did the equilibrium shift when you added NaOH to the solution? (Hint: Think about what NaOH will react with and how that result will affect the other components present in the solution.) System No. 3: BiCl3(aq) + H2O(l) ⇌ 2H+(aq) + BiOCl(s) + 2Cl-(aq) Solutions | Observations BiCl3 mixed with water | milky white w/ ppt forming Mixture plus HCl | clear with white ppt Mixture diluted with water | cloudy white liquid 6. Explain how the equilibrium shifted when you dissolved the BiCl3 in excess water. 7. Explain how the equilibrium shifted after the addition of HCl. 8. Explain how the equilibrium shifted after dilution.

Shyam P.

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Calculate the equilibrium concentrations of N2O4 and NO2 at 25°C in a vessel that contains an initial N2O4 concentration of 0.0396 M. The equilibrium constant Kc for the reaction N2O4(g) ⇌ 2NO2(g) is 4.64×10^-3 at 25°C. The equilibrium constant Kp for the reaction C(s) + H2O(g) ⇌ CO(g) + H2(g) is 2.44 at 1000 K. The initial partial pressures are PH2O = 1.19 atm, PCO = 1.09 atm, and PH2 = 1.46 atm. Part A: What is the equilibrium partial pressure of H2O? Express your answer with the appropriate units. Part B: What is the equilibrium partial pressure of CO? Phosphine (PH3) decomposes at elevated temperatures, yielding gaseous P2 and H2: 2PH3(g) ⇌ P2(g) + 3H2(g) with Kp = 398 at 873 K. Part A: If the initial partial pressures are PPH3 = 0.0270 atm, PP2 = 0.863 atm, PH2 = 0.512 atm, calculate Qp. Gaseous indium dihydride is formed from the elements at elevated temperature: In(g) + H2(g) ⇌ InH2(g) with Kp = 1.48 at 973 K. Partial pressures measured in a reaction vessel are: PIn = 0.0650 atm, PH2 = 0.0300 atm, PInH2 = 0.0750 atm. Part A: Calculate Qp. Part B: Determine the direction of reaction to attain equilibrium. Part C: Determine the equilibrium partial pressure of In. Part D: Determine the equilibrium partial pressure of H2. Part E: Determine the equilibrium partial pressure of InH2.

Dinesh S.


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Transcript

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00:01 In the given question, concentration of fe, no3 whole thrice is equal to 2 multiply by 10 to the power minus 3 mole.
00:15 And the volume of fe, no3 whole thrice is equals to 5 ml.
00:28 Now the concentration of kscn is equal to 2 multiply by 10 to the power minus 3 mole.
00:38 The volume of k s cn is equals to 3ml the equilibrium constant sorry the equilibrium concentration equilibrium concentration f e cn f e cn fescn to positive is equal to 7 multiply by 10 to the power minus 5 molar so the volume of water is equal to 2 ml.
01:29 Total volume is equal to 5 plus 3 plus 2 is equal to 10 ml.
01:40 Now the initial f .e2 positive mole.
01:47 Initial concentration f2 positive is equals to m fes, sorry fe and o3 whole thrice, by volume of fe, no3 whole thrice.
02:10 2 multiply by the concentration of fes, n03 whole thrice is 2 multiplied by 10 to the power minus 3, multiply by 5, multiply by 1 by 1 ,000.
02:23 That is equals to 1 multiplied by 10 to the power minus 5 mole.
02:28 This is the initial concentration of, sorry, initial moles of fe 2 positive.
02:33 This is the initial moles of f2 positive...
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