Two cards are randomly chosen (without replacement) from a standard deck of 52 cards. Let B be the event that both cards are aces; let As be the event that the ace of spades is chosen; let A be the event that at least one ace is chosen. Find the conditional probabilities: (a) P(B | As) (b) P(B | A) (Note: In As, 's' is the subscript)
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Since we know that the ace of spades is already chosen, there are only 51 cards left in the deck, and 3 of them are aces. Show more…
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Two cards are randomly chosen without replacement from an ordinary deck of 52 cards. Let $B$ be the event that both cards are aces, let $A_{s}$ be the event that the ace of spades is chosen, and let $A$ be the event that at least one ace is chosen. Find (a) $P\left(B | A_{s}\right)$ (b) $P(B | A)$
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