Two cards are randomly chosen without replacement from an ordinary deck of 52 cards. Let $B$ be the event that both cards are aces, let $A_{s}$ be the event that the ace of spades is chosen, and let $A$ be the event that at least one ace is chosen. Find (a) $P\left(B | A_{s}\right)$ (b) $P(B | A)$
Added by John B.
Step 1
Since we know that one of the cards is the ace of spades, we are essentially choosing one card from the remaining 51 cards. There are 3 other aces in the deck, so the probability is $\frac{3}{51} = \frac{1}{17}$. Show more…
Show all steps
Your feedback will help us improve your experience
Ahmad Reda and 58 other Probability educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Recommended Videos
Chai S.
Two cards are randomly selected from a deck of 52 standard cards without replacement. Use total probability theorem to find the probability that the second card is an Ace.
Audrey F.
Let two cards be dealt successively, without replacement, from a standard 52-card deck. Find the probability of the event. two aces
Jainendra O.
Recommended Textbooks
Probability with Applications in Engineering, Science, and Technology
Probability and Statistics for Engineers and Scientists
Applied Statistics and Probability for Engineers
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD