00:01
Hello students, in this question it's being said that assume the mating of two dogs from different breeds that both show an excessive bleeding disorder and in one breed the condition is autosomal recessive and in other breed it is a sex -linked recessive disorder.
00:36
The dogs used are the affected male which is a breed called as lab and affected female and the breed name is sober man.
01:02
So we use two breeds in which males are affected and females are affected and the regarding the progeny, the progeny we get after breeding these two dog breeds.
01:21
So in the progeny all we get all normal females and all affected males.
01:39
Now the based on this the question asked is which breed has sex -linked disorder and what is the genotype for that breed at both loci because we have one of the loci is autosomal another is the sex chromosome.
02:01
So first we are supposed to find which breed has a sex -linked disorder among the two and what is the genotype of that breed at both the loci.
02:14
So here the terminology i will be using is for sex chromosomes x and y and for the autosomal chromosome i will be writing a.
02:29
So for the wild type i will add plus and for the affected one i will add negative in case of sex chromosomes and in case of autosome the wild type will be a and affected will be a.
02:47
So now consider the male affected male has a is suppose a sex -linked disorder...