Hemophilia is a recessive inherited blood disorder. Hemophiliacs can't form blood clots. While minor cuts aren't usually a problem, hemophiliacs have significant problems with internal bleeding. The gene for hemophilia A is on the X chromosome. A woman who is a carrier for hemophilia (she has the allele but not the trait) has children with a normal (non-hemophiliac) man. What will be the genotypes and phenotypes of their offspring? Show your work (a Punnett square will be helpful here!).
Added by Diego B.
Step 1
First, let's assign the alleles. We'll use "H" for the normal allele and "h" for the hemophilia allele. Since the woman is a carrier, her genotype is X^H X^h (one normal allele and one hemophilia allele). The man is normal, so his genotype is X^H Y (he has one Show more…
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Hemophilia is a recessive sex linked trait and is carried on the X chromosome. Sara who had hemophilia married a man (Tim) who did not have hemophilia. They had 2 children, a boy and a girl. Use this punnett square to explain whether (and why) each kid had hemophilia or not. Be thorough for full credit.
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In humans, hemophilia (Xh) is a recessive sex-linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won't ever be carriers). Show the Punnett Square of a man who has hemophilia with a woman who is a carrier. What are the resulting genotype and phenotype proportions? A woman who is a carrier (XHXh) marries a non-hemophilic man. Show the Punnett Square. What are the resulting genotype and phenotype proportions? Please show the Punnett square for both examples and the genotype and phenotype ratios. Thank you.
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