The bacterial culture contains 100 cells at a certain point in time. Sixty minutes later, there are 450 cells. Assuming exponential growth, determine the number of cells present at time t.
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71828) - \( k \) is the growth rate - \( t \) is the time Given that \( N_0 = 100 \) cells and \( N = 450 \) cells after \( t = 60 \) minutes, we can substitute these values into the formula to find the growth rate \( k \). So, \( 450 = 100 * e^{60k} \). To Show more…
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