00:01
Here the given data is given data.
00:07
Here we have the constant density system, constant density system, density system and here volume is also constant, volume is also constant.
00:26
Then we have given f1 is equal to 200 liter per minute.
00:34
Number 1, here we have the f2 that is 300 liter per minute.
00:43
Number 2, then c1 0 .5 mole per liter.
00:52
Number 3, here c2 that is 0 .25 mole per liter that is number 4 and here tank dia means diameter that is d, it is 1 meter.
01:11
Now liquid level, liquid level at steady rate, at steady state is equal to 1 .28 meter.
01:28
Now apply mass balance, now apply mass balance, mass balance over the reaction, over the reaction.
01:51
So we have input, input minus output is equal to accumulation that is accumulation.
02:05
Now here we have the pf1 t plus pf2 t minus pf t is equal to dv upon dt.
02:30
We know that v is volume is constant, constant.
02:36
Now pf1 t plus pf2 t minus pf t is equal to 0.
02:52
Now f1 t plus f2 t minus f t is equal to 0.
03:05
This is the fifth equation.
03:08
Then now apply, now apply mass, now apply mass balance, mass balance over the reaction, over the reaction.
03:29
So here we have f1 t, c1 t plus f2 t, here c2 t minus f t and c t is equal to d upon dt and here we have the b, c and here we have the now f1 t, c1 t plus f2 t, c2 t minus f t, f t is equal to v, f t and then c t and here v is equal to d, c t upon dt.
04:32
This is equation sixth.
04:36
Now total variables, total variables, total variables are f1 t, f1 t then c2 f then c1 t minus here we have the f t, c t is equal to b.
05:11
So the total variables that is the b, d, c t upon dt...