Question

The CRV $X$ has the PDF given by $f(x) = \begin{cases} \frac{k}{(x+1)^3}, & x \ge 0\\ 0, & \text{otherwise} \end{cases}$. (a) Find the value of $k$. (b) Find $E(X+1)$, and hence $E(X)$.

          The CRV $X$ has the PDF given by $f(x) = \begin{cases} \frac{k}{(x+1)^3}, & x \ge 0\\ 0, & \text{otherwise} \end{cases}$.
(a) Find the value of $k$.
(b) Find $E(X+1)$, and hence $E(X)$.

The CRV X has the PDF given by f(x) = (k)/((x+1)^3), x ≥ 0
0, otherwise.
(a) Find the value of k.
(b) Find E(X+1), and hence E(X).

Added by Jennifer G.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Mutahar Mehkri

02/10/2021

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This is because the total probability of all possible outcomes must sum to 1. Show more…

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Hi need help ASAP, Thank you! Please write as detailed as possible, I will denfinitely upvote! The CRV x has the PDF given by f(x)={((k)/((x+1)^(3)),x>=0),(0, otherwise ):}. (a) Find the value of k. (b) Find E(x+1), and hence E(x). k The CRV X has the PDF given by f(x) 0, otherwise a)Find the value of k. b)Find E(X+1),and hence E(x)