How can we prepare a 100 mL of 0.2 M CuSO4 solution from a 250 mL of 0.4 M CuSO4·5H2O solution? Clearly state the lab equipment you will use. If there are any calculations you need to do, show your work properly.
Added by Daniel W.
Step 1
4 M CuSO4·5H2O solution needed to make 100 mL of 0.2 M CuSO4 solution using the formula M1V1 = M2V2. Given: M1 = 0.4 M V1 = 250 mL M2 = 0.2 M V2 = 100 mL Plugging in the values: 0.4 * 250 = 0.2 * V2 100 = 0.2 * V2 V2 = 500 mL Show more…
Show all steps
Your feedback will help us improve your experience
Vishal Sharma and 95 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Describe how to prepare 100 mL of a 15% CuSO4 solution from a 2 M CuSO4 stock solution. Hint: You will need to calculate the molecular weight of CuSO4.
David C.
We want to prepare Fehlings solution but dont know how many grams CuSO4 to add in our watersolution. How would we figure it out if the volume is supposed to be 50ml and the solution has to be 0,1M?
Describe how you would prepare $500.0 \mathrm{~mL}$ of $0.6500 \mathrm{M}$ sodium sulfate solution starting with (a) solid sodium sulfate. (b) $2.500 \mathrm{M}$ sodium sulfate solution.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD