Question

9. int_{1}^{3} (2x-1)^{4} dx 10. int_{1}^{2} (2x+4)(x^{2}+4x-8)^{3} dx 11. int_{-1}^{1} x^{2}(x^{3}+1)^{4} dx 12. int_{1}^{2} (x^{3}+frac{3}{4})(x^{4}+3x)^{-2} dx 13. int_{1}^{5} xsqrt{x-1} dx 15. int_{0}^{2} 2xe^{x^{2}} dx 17. int_{0}^{1} (e^{2x}+x^{2}+1) dx

          9. int_{1}^{3} (2x-1)^{4} dx
10. int_{1}^{2} (2x+4)(x^{2}+4x-8)^{3} dx
11. int_{-1}^{1} x^{2}(x^{3}+1)^{4} dx
12. int_{1}^{2} (x^{3}+frac{3}{4})(x^{4}+3x)^{-2} dx
13. int_{1}^{5} xsqrt{x-1} dx
15. int_{0}^{2} 2xe^{x^{2}} dx
17. int_{0}^{1} (e^{2x}+x^{2}+1) dx

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$9. int1^3 (2x-1)^4 dx 10. int1^2 (2x+4)(x^2+4x-8)^3 dx 11. int-1^1 x^2(x^3+1)^4 dx 12. int1^2 (x^3+frac34)(x^4+3x)^-2 dx 13. int1^5 xsqrtx-1 dx 15. int0^2 2xe^x^2 dx 17. int0^1 (e^2x+x^2+1) dx$

Added by Jaqueline A.

Finite Mathematics and Applied Calculus

Stefan Waner, Steven Costenoble 5th Edition

Chapter 13

Instant Answer

Solved by Expert Vincenzo Zaccaro

05/15/2024

Step 1

First, you need to identify the function that you are integrating. This is the function that is inside the integral sign. Show more…

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