How many distinct divisors does the integer 2^16 - 1 have?
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So, \(2^{16}-1 = (2^8 + 1)(2^8 - 1)\). We can further factorize \(2^8 - 1\) as \((2^4 + 1)(2^4 - 1)\). And \(2^4 - 1\) can be factored as \((2^2 + 1)(2^2 - 1)\). Show more…
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