A) How many distinct divisors does the integer 2^35^67^8 have?
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It is \(2^{3} 5^{6} 7^{8}\). The number of divisors of a number is given by the product of one more than each of the exponents in its prime factorization. So, the number of divisors of \(2^{3} 5^{6} 7^{8}\) is \((3+1)(6+1)(8+1) = 4*7*9 = 252\). Show more…
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