How many grams (g) of copper are deposited during electrolysis when a current of 0.198 is passed for 1.69 hours through a solution of copper(II) sulphate?
Added by Hannah C.
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5 g/mol Faraday's constant (F) = 96,485 C/mol Z = 63.5 / 2 * 96485 Z = 0.0003297 g/C Show more…
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