3. How many grams of each of the following per kilogram of water in your car radiator are needed to give equal protection against freezing down to -10°C? (a) Methyl alcohol, CH3OH, b.p. 64.6°C. (b) Ethylene glycol, C2H4(OH)2, b.p. 197.2°C. In spite of higher cost, what advantage does ethylene glycol possess over methyl alcohol as a winter antifreeze and/or summer coolant? (a) _______ (b) _______
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- The freezing point of pure water is 0°C. To protect against freezing down to -10°C, a freezing point depression of 10°C is needed. Show more…
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Pruthvi R.
$K_{t}$ for water is $1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1} .$ If your automobile radiator holds $1.0 \mathrm{~kg}$ of water, how many grams of ethylene glycol $\left(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}_{2}\right)$ must you add to get the freezing point of the solution lowered to $-2.8^{\circ} \mathrm{C}$ ? (a) $39 \mathrm{~g}$ (b) $93 \mathrm{~g}$ (c) $72 \mathrm{~g}$ (d) $27 \mathrm{~g}$
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