00:01
Hi, in this question we are having three parts.
00:03
In the first part of the question, we are asked to calculate the volume of naoh that is required to neutralize the hcl with concentration 0 .0500 molar and volume 5 ml.
00:16
Here we can say that at equivalence point, the moles of base are equal to moles of acid and moles are given by molarity into volume.
00:25
For naoh, we will use m1v1 that will be equal to m2v2.
00:32
This is for hcl.
00:33
We need to calculate the v1 value.
00:35
It will be equal to m2v2 divided by m1.
00:39
Now we can substitute the values here in this manner.
00:43
Now we can eliminate the common unit molar from here and on solving this we are getting the v1 value equals to 2 .5 ml.
00:53
This is the answer of first part.
00:56
Now in second part, we are asked to calculate the volume of naoh that is required to neutralize hno3 that has concentration and volume in this manner...