Question

How many mL of 0.250 M KMnO4 are needed to react with 3.55 g of Iron (II) sulfate FeSO4? The reaction is as follows: 10FeSO4(aq) + 2KMnO4(aq) + 8H2SO4(aq) → 5Fe2(SO4)3(aq) + 2MnSO4(aq) + K2SO4(aq) + 2H2O(l)

Name: how many ml of 0250 m kmno4 are needed to react with 355 g of iron ii sulfate feso4 the reaction is as follows10feso4aq 2kmno4aq 8h2so4aq 5fe2so43aq 2mnso4aq k2so4aq 2h2ol 69018
Uploaded: 2022-02-06T04:08:55-08:00
Duration: 5 min 19 s
Channel: Adedamola Opalade
Description: how many ml of 0250 m kmno4 are needed to react with 355 g of iron ii sulfate feso4 the reaction is as follows10feso4aq 2kmno4aq 8h2so4aq 5fe2so43aq 2mnso4aq k2so4aq 2h2ol 69018

          How many mL of 0.250 M KMnO4 are needed to react with 3.55 g of Iron (II) sulfate FeSO4? The reaction is as follows: 10FeSO4(aq) + 2KMnO4(aq) + 8H2SO4(aq) → 5Fe2(SO4)3(aq) + 2MnSO4(aq) + K2SO4(aq) + 2H2O(l)

Added by Lonnie S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adedamola Opalade

02/06/2022

Step 1

Given: Fe = 55.845 g/mol, S = 32.065 g/mol, O = 15.999 g/mol Molar mass of FeSO4 = 55.845 + 32.065 + (4 x 15.999) = 151.908 g/mol Show more…

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How many mL of 0.250 M KMnO4 are needed to react with 3.55 g of Iron (II) sulfate FeSO4? The reaction is as follows: 10FeSO4(aq) + 2KMnO4(aq) + 8H2SO4(aq) → 5Fe2(SO4)3(aq) + 2MnSO4(aq) + K2SO4(aq) + 2H2O(l)