00:01
The question is how many acetyl co -a, fadh and nadh fadh fadh 2 and nadh are produced after the beta oxidation of steroid co -a.
00:25
So, steroil coa is of 18 carbon compound and how many fadh 2, nadh2 and astilcoa are produced? and also how many atps.
00:39
Okay, so sterile coa being a 18 carbon compound, how the reaction would be is sterol foa plus 8 foa plus 8 fad plus 8 nad plus 8 h2o as bit oxidation releases lot of amount of water gives rise to 9 acetyl coi plus 8 fadh 2 plus 8 nadh plus 8 nadh plus is.
01:34
Now this is how the sterile coi will undergo the reaction.
01:42
So generally what happens, 1 beta oxy cycle so one beta oxidation is going to produce one fadh 2 1 nadh 2 and 1 acetyl coi now since the sterile coi is a 18 carbon compound it will be going on cycle cycle cycle of bit oxidation will go on till the astil coa of even number that is till the 9 no two numbers of astral coi are being remained so nine astral coi will be generated it 18 divided by 2 gives you 9 therefore 9 astral coi will be generated as the cycle has to go on till the complete 18 carbon chain is been broken down to two molecules of carbon that is two molecules of astral coa which requires or which yields nine acetyl coa now to do the math of this 9 acetyl co -a is going to be multiplied by approximately 1280ps.
03:01
So, acetal co -a generally generates 1280ps.
03:05
1 fadh2 is going to be equivalent to 1 .5.
03:11
So let's assume it as 2 and nadh2, let's assume it as 3 for the easy calculation.
03:18
9 into 12 gives you 1 .8.
03:22
Similarly we have 8 fadh 2.
03:26
So 8 into 2 because value of 1 fadh 2 is equal to 280ps.
03:33
So 8 into 2 is going to give you 16 80ps and we have 8 nadh 2 and value of 1 nadh is equivalent to 3...