How many moles of O₂ would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 76.1% yield? 2 NO (g) + O₂ (g) → 2 NO₂ (g)
Added by Joseph B.
Step 1
According to the balanced equation, 2 moles of NO₂ are produced for every 1 mole of O₂. So, if we have 13.0 moles of NO₂, we can find the moles of O₂ required for the theoretical yield: 13.0 mol NO₂ × (1 mol O₂ / 2 mol NO₂) = 6.5 mol O₂ Show more…
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