How many moles of O₂ would be required to generate 13.0 mol of NO₂ in the reaction below, assuming the reaction has only a 74.5% yield? 2 NO(g) + O₂(g) → 2 NO₂(g)
Added by Sean E.
Step 1
Given the balanced chemical equation: 2 NO(g) + O₂(g) → 2 NO₂(g) According to the stoichiometry of the reaction, 1 mole of O₂ is required to produce 2 moles of NO₂. Therefore, 1 mole of O₂ produces 2 moles of NO₂. Show more…
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