00:01
So we have here aluminum reacts with oxygen to form aluminum oxide.
00:05
So first we got to make a balanced equation.
00:08
So aluminum plus some amount of oxygen yields some amount of aluminum oxide.
00:21
Well, we can see here that we, let's just multiply this by two.
00:28
So that way there's four aluminum and six oxygen.
00:33
So 302.
00:35
Okay, so we have our balanced equation.
00:39
So for part a, how many moles of o2 are needed to react with 1 .44? moles of aluminum.
00:47
So there's a 4 to 3 ratio here of aluminum to aluminum to oxygen.
00:55
So if there's 1 .44 here, and we need x as our moles of o2.
01:02
So we can just set up the proportion 3 over 4.
01:05
Is equal to x over 1 .44.
01:09
We solve this, we get, with a simple algebra, 1 .08 moles of 02...