How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. KNO3(s) → K2O(s) + N2(g) + O2(g)
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The number of moles = mass / molar mass = 58.6 g / 101.11 g/mol = 0.579 moles of KNO3. Show more…
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How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.1 g/mol. 2 KNO3(s) -> 2 KNO2(s) + O2(g) Given: - 58.6 g KNO3 - Molar mass of KNO3 = 101.1 g/mol Calculations: - Moles of KNO3 = 58.6 g / 101.1 g/mol = 0.579 mol KNO3 - According to the balanced equation, 2 moles of KNO3 produce 1 mole of O2. - Therefore, moles of O2 formed = 0.579 mol KNO3 * (1 mol O2 / 2 mol KNO3) = 0.290 mol O2 Answer: 0.290 moles of oxygen are formed when 58.6 g of KNO3 decomposes.
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