Find the capacitance (C) of the below given capacitor, which is filled with two different dielectric materials with dielectric constants of ?1 and ?2. The first dielectric has a thickness of d1 and the other one has a thickness of d2, such that d = d1 + d2, where d is the distance between the two plates of the capacitor. The surface area of the capacitor is A. a. C = ?0 A d1 d2 / (?1 d2 + ?2 d1) b. C = ?0 A ?1 ?2 / (?2 d1 + ?1 d2) c. C = ?0 A ?1^2 / (?2 d1 + ?1 d2) d. C = ?0 A ?2^2 / (?2 d1 + ?1 d2) e. C = ?0 A ?1 ?2 / (d1 d2 (?1 + ?2))
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First, we can consider the capacitor as two separate capacitors connected in series, one with dielectric material 1 and the other with dielectric material 2. Show more…
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