At t = 0 the switch S is closed with the capacitor uncharged. If C = 40 ?F, ? = 50 V, and R = 5.0 k?, how much energy is stored by the capacitor when I = 2.0 mA? a. 40 mJ b. 32 mJ c. 36 mJ d. 28 mJ e. 20 mJ The correct answer is: 32 mJ
Added by Bora A.
Close
Step 1
First, we need to find the voltage across the capacitor when the current is 2.0 mA. We can use the formula for the charging of a capacitor in an RC circuit: \[V(t) = \varepsilon (1 - e^{-t/RC})\] Show more…
Show all steps
Your feedback will help us improve your experience
Nishant Kumar and 73 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
how to solve this question
Timothy J.
how to solve this
Nishant K.
In the circuit shown in the figure, $R_{1}=10.0 \Omega, R_{2}=4.00 \Omega$, and $R_{3}=10.0 \Omega$, and the capacitor has capacitance $C=2.00 \mu \mathrm{F}$. a) Determine the potential difference, $\Delta V_{\mathrm{C}}$, across the capacitor after switch S has been closed for a long time. b) Determine the energy stored in the capacitor when switch S has been closed for a long time. c) After switch S is opened, how much energy is dissipated through $R_{3}$ ?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD