HW 1) $(1+x^2)y' + 2xy = \frac{1}{(1+x^2)y}$ 2) $y' - \frac{1+x}{3x}y = y^4$ 3) $y' - y = xy^{1/2}$, $y(0) = 4$
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Step 1: The given differential equation is y'-y=x y^(1/2) Show more…
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