Question

Simplify the following expressions. Determine any restrictions. i) \frac{4}{x+3} + \frac{5}{4x+12} ii) \frac{t-2a}{t} - \frac{4t+a}{ta} - \frac{3t-4a}{a} iii) \frac{2x}{x^2-4x-5} + \frac{3x}{x-5} The relation between the period of a pendulum, T, and its length L, is T = 2\pi\sqrt{\frac{1}{g}}, where the acceleration due to gravity, g = 9.8 m/s^2. Solve for L to two decimal places.

          Simplify the following expressions. Determine any
restrictions.
i) \frac{4}{x+3} + \frac{5}{4x+12}
ii) \frac{t-2a}{t} - \frac{4t+a}{ta} - \frac{3t-4a}{a}
iii) \frac{2x}{x^2-4x-5} + \frac{3x}{x-5}
The relation between the period of a pendulum, T, and its
length L, is T = 2\pi\sqrt{\frac{1}{g}}, where the acceleration due to
gravity, g = 9.8 m/s^2. Solve for L to two decimal places.

Simplify the following expressions. Determine any
restrictions.
i) (4)/(x+3) + (5)/(4x+12)
ii) (t-2a)/(t) - (4t+a)/(ta) - (3t-4a)/(a)
iii) (2x)/(x^2-4x-5) + (3x)/(x-5)
The relation between the period of a pendulum, T, and its
length L, is T = 2π√((1)/(g)), where the acceleration due to
gravity, g = 9.8 m/s^2. Solve for L to two decimal places.

Added by Wendy S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ankit Gupta

07/09/2020

Step 1

To simplify the expression 4x+12, we can combine like terms. Since there are no other terms with x, we can leave the 4x as it is. The constant term 12 can also be left as it is. So, the simplified expression is 4x+12. Show more…

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I need help witg these 2 questions pls Simplify the following expressions.Determine any restrictions 4 5 i) + x+3 4x+12 t-2a 4t+a 3t-4a ii) t ta a 2x 3x + x-5 iii) x2-4x-5 The relation between the period of a pendulum,T,and its 1 length L,is T=2 where the acceleration due to gravity,g=9.8 m/s2.Solve for Lto two decimal places