Consider the function $f(z) = 2z^3 - 15z^2 - 300z + 2$, $-9 \le z \le 16$. The absolute minimum of $f(z)$ (on the given interval) is at $z = $ and the absolute minimum of $f(z)$ (on the given interval) is The absolute maximum of $f(x)$ (on the given interval) is at $x = $ and the absolute maximum of $f(z)$ (on the given interval) is (Note: If a function has two x values at which a maxima or minima occur, enter them both separated by a comma.)
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To find the critical points, we need to find the values of x where the derivative of f is equal to zero or undefined. The derivative of f with respect to x is: f'(x) = 30x^14 Setting f'(x) equal to zero, we get: 30x^14 = 0 Solving for x, we find that x = Show more…
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