00:01
For question number one, to identify the pressure of a hot water stream, we need to write first the given.
00:11
For the hot stream temperature, we have t1, which is equals to 80 degrees celsius.
00:18
The hot stream flow rate, which is our m1, is 0 .5 kilogram per seconds.
00:24
The cold stream temperature that is our t2 is 20 degrees celsius.
00:30
The mixture temperature that is our tm is 42 degrees celsius.
00:36
And the cold stream flow, which is the thing that we need to find, is our m2, and the pressure that is 250 kpa.
00:46
For the solution, for the mixture of hot stream and cold stream, the heat supplied by hot stream is equal to heat gain by cold stream.
00:56
So by applying energy balance equation, we get heat supply by hot stream.
01:01
Hot stream.
01:03
So we have qh is equals to m1 cp times t1 minus tm and the heat gain by cold stream is qc is equals to m2 cp times tm minus t2.
01:23
Equating this two we will get m1 cp times t1 t m minus t2 and canceling cp as pressure is constant throughout so we will have m1 t1 minus tm is equals to m2 tm minus t2 so by putting all the value 0 .5 80 minus 42 is equals to m2 42 minus 20 therefore our m2 will be 0 .8636363 per seconds.
02:17
So the cold stream mass flow rate is 0 .863636 kilogram per seconds.
02:26
For question number six, we need to determine the rate of heat transfer in the heat exchanger and the exit temperature of the hot water.
02:37
First is we need to write the give.
02:39
So the mass flow rate of cold water, that is 0 .6 kilograms per seconds...