Find the force member at ED? G F E A B C D 4 ft 4 ft 4...

Transcript

00:01 Hello students in this question we have to calculate the moment of this 200 pound force about point o using vagnon's theorem so first of all let's see what vagnon's theorem is according to vennignon's theorem the moment of a force about the point moment of a force about a point is equal to about a point now this moment is equal to the moment of the sorry sum of the moment of the components of the moment of the moment of the moment of components of this force about that point.

00:44 So using this theorem we can calculate the moment of this force.

00:51 So the figure is given in somewhere like this.

00:55 Here we have a force which is acting like in this direction a 200 pound force is acting and we are given that this distance is 5 feet and this distance this total distance here is 10 feet and we have to calculate the moment of this force about point o okay so using valagnone's theorem first we will make the rectangular components of this force so the rectangular components of this force will be like this and this here we have an angle of 40 degrees so this component will be 200 cost 40 degree and this component will have a magnitude of 200 sine 40 degrees okay so the more we have to calculate the moment of this force about 0 so we can write that the torque will be equal to the torque due to the sum of the torque due to its rectangular components okay so the torque due to 200 goes 40 degree pound force and plus torque due to 200 sine 40 degree pound force so first of all let's see the torque of this so the formula for torque is r vector cross f vector.

02:17 R vector cross f vector means the force times the value of distance of the point from which the force is acting from the point from where we have to calculate the moment so let's say this distance will be equal to let's say this distance is capital r so the torque will be r times force times the value of s -theta from here we can see that the value of s -theta and theta is 180 degree.

02:46 So this torque will be equal to 0 plus here we will have 200 sine 40 degree times the distance that is r times the value of sine 90 degree and sine 90 degree is equal to 1 so the torque will be equal to this only...

Question

Find the force member at ED? G F E A B C D 4 ft 4 ft 4 ft 600 lb 600 lb 800 lb O a. 1200 lb (T) O b. 800 lb (T) O c. 1131 lb (T) O d. 566 lb (T) ft

Question

Find the force member at ED? G F E A B C D 4 ft 4 ft 4 ft 600 lb 600 lb 800 lb O a. 1200 lb (T) O b. 800 lb (T) O c. 1131 lb (T) O d. 566 lb (T) ft

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