00:01
I solve this question the probability of finding electron within 4 radius and that is for 1 s orbital.
00:08
So, first let us write the wave function.
00:11
So, the wave function for 1 s orbital 1 s orbital for hydrogen atom is equals to psi equals to 1 divided by under root pi e raise to the power p naught raise to the power minus 3 by 2 multiplied by e raise to the power minus r divided by p naught.
00:45
So, this is the wave function for cross s orbital for hydrogen atom.
00:54
So, now let us find the probability and it will be equals to integration psi 1 s star multiplied by psi 1 s d tau.
01:12
So, it will be equals to integration 0 to a 2 again integration 0 to pi and again integration 0 to 2 pi 1 divided by under root pi multiplied by 1 divided by p naught raise to the power 3 by 2 multiplied by e raise to the power minus r divided by p naught multiplied by 1 divided by under root pi multiplied by p naught raise to the power 3 by 2 multiplied by e minus r divided by p naught multiplied by r square d r sin theta d theta and d pi.
02:13
And it will be equals to integration 0 to p naught is the limit r square multiplied by e raise to the power minus 2 r divided by a naught d r integration 0 to pi sin theta d theta integration 0 to 2 pi is a limit and d pi.
02:47
So, it will be equals to 4 divided by a naught raise to the power 3 integration 0 to a naught multiplied by r square minus e raise to the power minus 2 r divided by a naught d r and after solving this we get the probability in terms to 1 minus 5 divided by e square...