If 1.50 mL of a stock solution of 12.0 M HCl is diluted to 25.0 mL, what is the new concentration? A. 200. M B. 3.10 M C. 0.450 M D. 0.720 M E. 0.500 M
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Step 1
Given: Volume of stock solution = 1.50 mL Concentration of stock solution = 12.0 M Moles of HCl = Concentration x Volume Moles of HCl = 12.0 M x 1.50 mL Moles of HCl = 18.0 mmol (millimoles) Show more…
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