If (3x^2 + 3x + xy = 1) and (y(1) = -5), find (y'(1)) by implicit differentiation.
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\[ \frac{d}{dx} (3x^2 + 3x + xy) = \frac{d}{dx} (1) \] \[ 6x + 3 + x\frac{dy}{dx} + y = 0 \] Show more…
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