If 42.4 mL of 0.212 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solution? Express the mass in grams to three significant digits.
Added by David M.
Step 1
Given: Volume of HCl solution = 42.4 mL = 0.0424 L Molarity of HCl solution = 0.212 M Moles of HCl = Molarity x Volume Moles of HCl = 0.212 mol/L x 0.0424 L Moles of HCl = 0.00899 moles Show more…
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