Question

If a particle at position $\vec{r} = (4.5 \ m) \hat{i}$ experiences a force $\vec{F} = (6.0 \ N)\hat{i} - (2.0 \ N)\hat{j}$, what is the torque on this particle about the origin? $\vec{\tau} = (-27 \ Nm)\hat{k}$ $\vec{\tau} = (-9.0 \ Nm)\hat{k}$ $\vec{\tau} = (+27 \ Nm)\hat{i} - (9.0 \ Nm)\hat{j}$ $\vec{\tau} = (+9.0 \ Nm)\hat{k}$ $\vec{\tau} = (+27 \ Nm)\hat{k}$

Name: if a particle at position vecr 45 m hati experiences a force vecf 60 nhati 20 nhatj what is the torque on this particle about the origin vectau 27 nmhatk vectau 90 nmhatk vectau 27 nmhati 90 10302
Uploaded: 2022-03-15T05:43:00-08:00
Duration: 4 min 5 s
Channel: Sahil Kumar
Description: if a particle at position vecr 45 m hati experiences a force vecf 60 nhati 20 nhatj what is the torque on this particle about the origin vectau 27 nmhatk vectau 90 nmhatk vectau 27 nmhati 90 10302

          If a particle at position $\vec{r} = (4.5 \ m) \hat{i}$ experiences a force $\vec{F} = (6.0 \ N)\hat{i} - (2.0 \ N)\hat{j}$, what is the torque on this particle about the origin?
$\vec{\tau} = (-27 \ Nm)\hat{k}$
$\vec{\tau} = (-9.0 \ Nm)\hat{k}$
$\vec{\tau} = (+27 \ Nm)\hat{i} - (9.0 \ Nm)\hat{j}$
$\vec{\tau} = (+9.0 \ Nm)\hat{k}$
$\vec{\tau} = (+27 \ Nm)\hat{k}$

if a particle at position vecr 45 m hati experiences a force vecf 60 nhati 20 nhatj what is the torque on this particle about the origin vectau 27 nmhatk vectau 90 nmhatk vectau 27 nmhati 90 10302

Added by Melissa C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sahil Kumar

03/15/2022

Step 1

Step 1: The torque $\vec{\tau}$ is given by the cross product of the position vector $\vec{r}$ and the force vector $\vec{F}$: $\vec{\tau} = \vec{r} \times \vec{F}$ Show more…

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If a particle at position $\vec{r} = (4.5 \ m) \hat{i}$ experiences a force $\vec{F} = (6.0 \ N)\hat{i} - (2.0 \ N)\hat{j}$, what is the torque on this particle about the origin? $\vec{\tau} = (-27 \ Nm)\hat{k}$ $\vec{\tau} = (-9.0 \ Nm)\hat{k}$ $\vec{\tau} = (+27 \ Nm)\hat{i} - (9.0 \ Nm)\hat{j}$ $\vec{\tau} = (+9.0 \ Nm)\hat{k}$ $\vec{\tau} = (+27 \ Nm)\hat{k}$