If a particle is fired from a ground level with initial velocity of v ft/sec and at an angle of ? with the horizontal, the range R of the projectile is given by R = v^2/16 sin ? cos ?. If v = 80 ft/sec, approximate the angles that result in a range of 150 ft: ? = 24.3° or 65.7°
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R = (sin θ)(cos θ) * 16 Substituting R = 150 ft and v = 80 ft/sec, we get: 150 = (sin θ)(cos θ) * 16 Show more…
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