If a person was standing 120 meters from a source and noticed an exposure rate of 101 m(R)/(h), what would be the exposure if he moved to 55 meters from the source?
Added by Patricia R.
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The exposure rate from a point source of radiation decreases with the square of the distance from the source. This can be expressed as: \[ \frac{E_1}{E_2} = \left(\frac{D_2}{D_1}\right)^2 \] where \(E_1\) is the exposure rate at distance \(D_1\), and \(E_2\) is Show more…
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