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39. If \overrightarrow{AB} = i + 4j - 2k and B is the point (5, 1, 3), find A. 40. If \overrightarrow{AB} = -7i + 3j + 8k and A is the point (-2, -3, 6), find B. 

          39. If \overrightarrow{AB} = i + 4j - 2k and B is the point (5, 1, 3), find A.
40. If \overrightarrow{AB} = -7i + 3j + 8k and A is the point (-2, -3, 6), find B.
39. If AB = i + 4j - 2k and B is the point (5, 1, 3), find A. 40. If AB = -7i + 3j + 8k and A is the point (-2, -3, 6), find B.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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If AB = i + 4j - 2k and B is the point (5, 1, 3), find A. 39. If AB = i + 4j - 2k and B is the point (5, 1, 3), find A. 40. If AB = -7i + 3j + 8k and A is the point (-2, -3, 6), find B.
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Transcript

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00:01 So if we're given that the vector a to b is i plus 4j minus 2k, and the point b is 513, we want to find what a is.
00:15 So first, let's go ahead and rewrite ab using the bracket notation just because i prefer that notation more.
00:25 So i's coefficient is the x component, j is coefficient, is the y component and k's coefficient is the z component oh not negative two or not negative z but negative two all right so we have that now let's think about what it means to be the vector ab so if we start from the point a and we add the vector ab to it we should land on b so since we want to find what a is what we're going to do is subtract ab over and we're going to get a is equal to b minus a, b.
01:09 So now we can go ahead and plug these values in.
01:14 So i'm going to plug in b as a vector...
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