If an object moves along the y-axis (marked in feet) so that its position at time x (in seconds) is given by f(x) = 72x - 12x^2, find the following. (A) The instantaneous velocity function v = f'(x) (B) The velocity when x = 0 and x = 2 sec (C) The time(s) when v = 0 (A) v(x) =
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Given f(x) = 72x - 12x^2, we find f'(x) by taking the derivative of each term: f'(x) = d/dx (72x) - d/dx (12x^2) f'(x) = 72 - 24x Show more…
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