Question

If $B = egin{bmatrix} a & b \ c & d end{bmatrix}$, find conditions on $a$, $b$, $c$, and $d$ such that $AB = BA$. (Select all necessary conditions.) $A = egin{bmatrix} 1 & 1 \ 0 & 1 end{bmatrix}$ d = 0 c = 0 a = d a = b b = c

          If $B = egin{bmatrix} a & b \ c & d end{bmatrix}$, find conditions on $a$, $b$, $c$, and $d$ such that $AB = BA$. (Select all necessary conditions.)
$A = egin{bmatrix} 1 & 1 \ 0 & 1 end{bmatrix}$
d = 0
c = 0
a = d
a = b
b = c

Added by Jacob R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

04/25/2022

Step 1

\[ A = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix} \] \[ B = \begin{bmatrix} a & b \\ c & d \end{bmatrix} \] Step 2: Compute the product $ AB $. \[ AB = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix} \begin{bmatrix} a & b \\ c & d \end{bmatrix} = Show more…

Show all steps

Thanks for your feedback!

If B = [a b; c d], find conditions on a, b, c, and d such that AB = BA. (Select all necessary conditions.) A = [1 1; 0 1] d = 0 c = 0 a = d a = b b = c