00:01
Hi there, so for this problem, we are told that the cost function that we are given for this, c of adds, is equal to 3 ,000, and then this plus 210 times adds, and then this plus six times adds to the 3 divided by 2.
00:26
Now, for the first question, for part a of this problem, we are asked about to find a total cost at a production level of 1 ,000 units.
00:37
So what we need to do is to evaluate the expression that we are given at 1 ,000.
00:42
So that will be then 3 ,000 plus 210 times 1 ,000.
00:49
And then this plus 6 times 1 ,000, elevated to 3 ,000.
00:56
Divided by 2.
00:58
Then let's use our calculator to see what value we obtained for this.
01:11
Okay, then the value that we obtained for this is we need to give this to the nearest cent.
01:22
So that will be then.
01:24
40 ,000.
01:27
Oh no, it's 402, 402, 737736.
01:38
066.
01:43
Remember, you need to answer this to the nearest cent.
01:50
Now we keep going.
01:52
For part b of this problem, the question is to find the average cost at a production level of 1 ,000.
02:02
Now, again, first of all, remember that the average cost is just the cost function divided by x.
02:09
So that will be then 3 ,000 divided by ads, then this plus 210 plus 6, and then we will have x elevated to 1 divided by 2, if i'm correct, because 3 divided by 2 minus 1 is 0 .5, sorry.
02:32
So now we just need to evaluate this at 1 ,000.
02:35
So let's do that.
02:39
This plus 210 plus 6 times 1 ,000 elevated to 1 divided by 2.
02:50
So let's see what value we obtained from our calculator.
02:54
Again, i think it is to the nearest cent.
03:02
Again, we need to include two decimal places.
03:08
Okay, let me see, let me use the calculator.
03:13
And the value that we obtained for this is 400.
03:17
0 .72 .74.
03:26
So that's a solution for part b of this problem...