If \frac{dy}{dx} = \frac{x}{\sqrt{9 + x^2}} and y = 5 when x = 4, then y equals (A) \sqrt{9 + x^2} - 5 (B) \sqrt{9 + x^2} (C) 2\sqrt{9 + x^2} - 5 (D) \frac{\sqrt{9 + x^2} + 5}{2} (E) none of these
Added by Mireia V.
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Step 1: Given that (dy)/(dx) = (x)/(\sqrt(9+x^(2))) and y = 5 when x = 4, we need to find the value of y. Show more…
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