If f(x) = 3x + 2e^4x + 5 where x ≠0, then d(f^(-1)(x)) at x = -2 is dx.
Added by Gregory S.
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To do this, we switch x and y and solve for y: x = 0.3y + 2e^(4y/5) x - 2e^(4y/5) = 0.3y 5(x - 2e^(4y/5)) = 1.5y 5x - 10e^(4y/5) = 1.5y 10e^(4y/5) + 1.5y = 5x e^(4y/5) + 0.15y = 0.5x So the inverse of f(x) is f^-1(x) = (1/4.8)ln(x/2 - 0.15x). Show more…
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