If f'(x) = 10x^4 + 1, find "+C" if f(1) = 6
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The antiderivative of 10x^4 is (10/5)x^5 = 2x^5 and the antiderivative of 1 is x. So, f(x) = 2x^5 + x + C, where C is the constant of integration. We know that f(1) = 6. So, we can substitute x = 1 into the equation to solve for C: 6 = 2(1)^5 + 1 + C Show more…
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