Question

If f(x) = |(x^2-12)(x^2+4)|, how many numbers in the interval -2 ≤ x ≤ 3 satisfy the conclusion of the Mean Value Theorem? A) None B) One C) Two D) Three E) Four (The "|" in the problem represents absolute value) 

          If f(x) = |(x^2-12)(x^2+4)|, how many numbers in the interval -2 ≤ x ≤ 3 satisfy the conclusion of the Mean Value Theorem?
A) None
B) One
C) Two
D) Three
E) Four
(The "|" in the problem represents absolute value)

Added by Nuria A.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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If f(x) = |(x^2-12)(x^2+4)|, how many numbers in the interval -2 ≤ x ≤ 3 satisfy the conclusion of the Mean Value Theorem? A) None B) One C) Two D) Three E) Four (The "|" in the problem represents absolute value)
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Transcript

-
00:01 Which we are given a function which is f of x which is equal we can write here at x squared minus 12 here we can write here value here is the x squared plus now how many numbers are interval we want to find numbers and the interval we can minus 2 here less equal to x or equal to 3 the satisfy the conclusion here of the mean value theorem so we are using here conclusion of the mean value theorem mean value theorem so let's solve this question and we are given a four options we want to choose which of the option is correct so here we can write the delta of x which is equal we can write the x squared minus 12 multiple we can write x squared plus so we can write here and we just simply find we can write x x x just to 4 minus 8 x squared plus minus 48 divide the delta x prime which is equal we can write here 4 x cube minus we can write 16 x interval that 2 to 3 minus 2 to 3 so we can write using this…
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