Question

If \(f(x) = x^3 + (x^5 + \log_4(x^2))^3\) then f'(x) equals a) \(3x^2 + (x^5 + \log_4(x^2))^2(5x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2}2x)\) b) \(x^2 + 3(x^5 + \log_4(x^2))^2(x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2})\) c) \(3x^2 + 3(x^5 + \log_4(x^2))^2(5x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2}2x)\) d) \(1 + 3(x^5 + \log_4(x^2))^2(4x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2})\) e) None of the above

          If
\(f(x) = x^3 + (x^5 + \log_4(x^2))^3\)
then f'(x) equals
a) \(3x^2 + (x^5 + \log_4(x^2))^2(5x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2}2x)\)
b) \(x^2 + 3(x^5 + \log_4(x^2))^2(x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2})\)
c) \(3x^2 + 3(x^5 + \log_4(x^2))^2(5x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2}2x)\)
d) \(1 + 3(x^5 + \log_4(x^2))^2(4x^4 + \frac{1}{\ln(4)} - \frac{1}{x^2})\)
e) None of the above

If
f(x) = x^3 + (x^5 + log4(x^2))^3
then f'(x) equals
a) 3x^2 + (x^5 + log4(x^2))^2(5x^4 + (1)/(ln(4)) - (1)/(x^2)2x)
b) x^2 + 3(x^5 + log4(x^2))^2(x^4 + (1)/(ln(4)) - (1)/(x^2))
c) 3x^2 + 3(x^5 + log4(x^2))^2(5x^4 + (1)/(ln(4)) - (1)/(x^2)2x)
d) 1 + 3(x^5 + log4(x^2))^2(4x^4 + (1)/(ln(4)) - (1)/(x^2))
e) None of the above

Added by Enrique C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Hast Aggarwal

11/30/2021

Step 1

Step 1: Use the power rule to find the derivative of x^3, which is 3x^2. Show more…

Show all steps

Thanks for your feedback!

If f(x)=x3+(x5+log4(x2))3 then f'(x) equals a) 1 1 3x2+(x5+log4(x2))2(5x4 n b) x2+3(x5+log4(x2))2(x 3x2+3(x5+log4(x2))2(5x4 T 1+3(x5+log4(x2))2(4x e) None of the above