If g(u)=int_9^(e^(u)) (cost^(9))/(t^(2))dt then g^(')(u)=||
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Step 1: Recognize g(u)=∫_{9}^{e^u} f(t) dt with f(t)=cos(t^9)/t^2; by the Fundamental Theorem of Calculus and the chain rule, g'(u)=f(e^u)·(d/du e^u). Show more…
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