Question

If g(x)=\sqrt(2-3x) use the definition of derivative to find g^(')(x). None of these g^(')(x)=-(2-3x)^(-(1)/(2)) g^(')(x)=-(3)/(2)(2-3x)^(-(1)/(2)) g^(')(x)=-(3)/(2)(2-3x)^((1)/(2)) g^(')(x)=-(1)/(2)(2-3x)^(-(1)/(2))

Name: if gxsqrt2 3x use the definition of derivative to find gx none of these gx 2 3x 12 gx 322 3x 12 gx 322 3x12 gx 122 3x 12 36435
Uploaded: 2023-06-22T20:45:22-08:00
Duration: 3 min 12 s
Channel: Gregory Higby
Description: if gxsqrt2 3x use the definition of derivative to find gx none of these gx 2 3x 12 gx 322 3x 12 gx 322 3x12 gx 122 3x 12 36435

          If g(x)=\sqrt(2-3x) use the definition of derivative to find g^(')(x).
None of these
g^(')(x)=-(2-3x)^(-(1)/(2))
g^(')(x)=-(3)/(2)(2-3x)^(-(1)/(2))
g^(')(x)=-(3)/(2)(2-3x)^((1)/(2))
g^(')(x)=-(1)/(2)(2-3x)^(-(1)/(2))

Added by Miriam H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Gregory Higby

06/22/2023

Step 1

None of these $g'(x) = -(2 - 3x)^{-1/2}$ $g'(x) = -\frac{3}{2}(2 - 3x)^{-1/2}$ $g'(x) = -\frac{3}{2}(2 - 3x)^{1/2}$ $g'(x) = -\frac{1}{2}(2 - 3x)^{-1/2}$ Show more…

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If g(x)=\sqrt(2-3x) use the definition of derivative to find g^(')(x). None of these g^(')(x)=-(2-3x)^(-(1)/(2)) g^(')(x)=-(3)/(2)(2-3x)^(-(1)/(2)) g^(')(x)=-(3)/(2)(2-3x)^((1)/(2)) g^(')(x)=-(1)/(2)(2-3x)^(-(1)/(2))