Question

if ln(x^2 - 34y) = x - y+6 and y(-5)=1, find y'(-5) by implicit differentation. y'(-5)=. an equation of the tangent line to the curve at the point (-5,1) is

Name: if lnx2 34y x y6 and y 51 find y 5 by implicit differentation y 5 an equation of the tangent line to the curve at the point 51 is 50527
Uploaded: 2023-11-25T04:59:24-08:00
Duration: 2 min 41 s
Channel: Adi S
Description: if lnx2 34y x y6 and y 51 find y 5 by implicit differentation y 5 an equation of the tangent line to the curve at the point 51 is 50527

          if ln(x^2 - 34y) = x - y+6 and y(-5)=1, find y'(-5) by implicit differentation. y'(-5)=. an equation of the tangent line to the curve at the point (-5,1) is

Added by Debra C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

11/25/2023

Step 1

Step 1: Differentiate both sides of the equation ln(x^2 - 34y) = x - y + 6 with respect to x using implicit differentiation. Show more…

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if ln(x^2 - 34y) = x - y+6 and y(-5)=1, find y'(-5) by implicit differentation. y'(-5)=. an equation of the tangent line to the curve at the point (-5,1) is