Question

If \( r(x)=3 x-1 \) and \( s(x)=2 x+1 \), which expression is equivalent to \( \left(\frac{r}{s}\right)(6) ? \) \( \frac{3(6)-1}{2(6)+1} \) \( \frac{(6)}{2(6)+1} \) \( \frac{36-1}{26+1} \) \( \frac{(6)-1}{(6)+1} \)

          If \( r(x)=3 x-1 \) and \( s(x)=2 x+1 \), which expression is equivalent to \( \left(\frac{r}{s}\right)(6) ? \)
\( \frac{3(6)-1}{2(6)+1} \)
\( \frac{(6)}{2(6)+1} \)
\( \frac{36-1}{26+1} \)
\( \frac{(6)-1}{(6)+1} \)

If r(x)=3 x-1 and s(x)=2 x+1, which expression is equivalent to ((r)/(s))(6) ?
(3(6)-1)/(2(6)+1)
((6))/(2(6)+1)
(36-1)/(26+1)
((6)-1)/((6)+1)

Added by Karen F.

Intermediate Algebra : Concepts and Applications

Marvin L. Bittinger, David J.… 10th Edition

Chapter 6

Instant Answer

Solved by Expert Lottie Adams

Step 1

Given \( r(x) = 3x - 1 \) and \( s(x) = 2x + 1 \). Show more…

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If \( r(x)=3 x-1 \) and \( s(x)=2 x+1 \), which expression is equivalent to \( \left(\frac{r}{s}\right)(6) ? \) \( \frac{3(6)-1}{2(6)+1} \) \( \frac{(6)}{2(6)+1} \) \( \frac{36-1}{26+1} \) \( \frac{(6)-1}{(6)+1} \)