Question

If the cylindrical wall of the Rotor is spinning at a tangential speed of 12.8 m/s, the radius is 9.74 m, the coefficient of static friction between the rider and the wall is 0.737, and the coefficient of kinetic friction is 0.574, what is the magnitude of the normal force in newtons on the 86.0 kg rider? Include units with your answer.

Name: if the cylindrical wall of the rotor is spinning at a tangential speed of 128 ms the radius is 974 m the coefficient of static friction between the rider and the wall is 0737 and the coeffic 87186
Uploaded: 2023-09-15T14:19:26-08:00
Duration: 5 min 14 s
Channel: Vishal Gupta
Description: if the cylindrical wall of the rotor is spinning at a tangential speed of 128 ms the radius is 974 m the coefficient of static friction between the rider and the wall is 0737 and the coeffic 87186

          If the cylindrical wall of the Rotor is spinning at a tangential speed of 12.8 m/s, the radius is 9.74 m, the coefficient of static friction between the rider and the wall is 0.737, and the coefficient of kinetic friction is 0.574, what is the magnitude of the normal force in newtons on the 86.0 kg rider? Include units with your answer.

Added by Sandra E.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

09/15/2023

Step 1

This force is provided by the friction between the rider and the wall. The centripetal force is given by the formula: F_c = m * v^2 / r where: F_c = centripetal force m = mass of the rider (86.0 kg) v = tangential speed of the wall (12.8 m/s) r = radius of the Show more…

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If the cylindrical wall of the Rotor is spinning at a tangential speed of 12.8 m/s, the radius is 9.74 m, the coefficient of static friction between the rider and the wall is 0.737, and the coefficient of kinetic friction is 0.574, what is the magnitude of the normal force in newtons on the 86.0 kg rider? Include units with your answer.