Question

If the vertical rod has a downward velocity $v = 2.5 \, ft/sec$ and upward acceleration $a = 3.6 \, ft/sec^2$ when the device is in the position shown, determine: (a) the corresponding angular acceleration $\alpha$ of bar AB (b) the magnitude of the acceleration of roller B Knowing that $\omega_{link} = 15.36 \, rad/sec$, $v_B = 19.36 \, ft/sec$. The value of R = 16 in.

Name: if the vertical rod has a downward velocity v 25 ftsec and upward acceleration a 36 ftsec2 when the device is in the position shown determine a the corresponding angular acceleration alpha o 17464
Uploaded: 2023-04-01T08:12:57-08:00
Duration: 2 min 56 s
Channel: Madhur L
Description: if the vertical rod has a downward velocity v 25 ftsec and upward acceleration a 36 ftsec2 when the device is in the position shown determine a the corresponding angular acceleration alpha o 17464

          If the vertical rod has a downward velocity $v = 2.5 \, ft/sec$ and upward acceleration $a = 3.6 \, ft/sec^2$ when the device is in the position shown, determine:
(a) the corresponding angular acceleration $\alpha$ of bar AB
(b) the magnitude of the acceleration of roller B
Knowing that $\omega_{link} = 15.36 \, rad/sec$,
$v_B = 19.36 \, ft/sec$.
The value of R = 16 in.

if the vertical rod has a downward velocity v 25 ftsec and upward acceleration a 36 ftsec2 when the device is in the position shown determine a the corresponding angular acceleration alpha o 17464

Added by Eric F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

04/01/2023

Step 1

Since the velocity and acceleration are given in ft/sec and $ft/sec^2$, we convert R from inches to feet: $R = 16 \, in = \frac{16}{12} \, ft = \frac{4}{3} \, ft$ The length of OA is $1.25R = 1.25 \times \frac{4}{3} = \frac{5}{3} \, ft$ Show more…

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If the vertical rod has a downward velocity $v = 2.5 \, ft/sec$ and upward acceleration $a = 3.6 \, ft/sec^2$ when the device is in the position shown, determine: (a) the corresponding angular acceleration $\alpha$ of bar AB (b) the magnitude of the acceleration of roller B Knowing that $\omega_{link} = 15.36 \, rad/sec$, $v_B = 19.36 \, ft/sec$. The value of R = 16 in.